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Old 09-02-2009, 12:59 PM   #1
caponewgp
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Registered: Aug 2009
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Command help


Im having a hard time figuring out exactly what this command does.
cut -f 5 -d: /etc/passwd | grep '^J' | wc l
I know that cut -f 5 will copy only the first and fifth fields but I cant figure out about the -d: /etc/passwd| grep '^J' will do.
Any general help will be appreciated Im just having a hard time finding anything about the -d argument on the internet.
 
Old 09-02-2009, 01:13 PM   #2
indienick
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Registered: Dec 2005
Location: London, ON, Canada
Distribution: Arch, Ubuntu, Slackware, OpenBSD, FreeBSD
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For future reference, typing
Code:
man command
will bring up a manual page describing the ins-and-outs of almost any program installed on your system.

The "-d" option sets the delimiter - the place at which to separate the elements in the file (/etc/passwd) by - in this case, it is the colon ":" character.

The output is then passed to the "grep" command where it is searching for the pattern dictated by "^J" - I don't know what this pattern dictates. That's for you to find out.

And the "wc -l" command means to count the number of lines that the "grep" command prints.
 
  


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