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Old 03-25-2012, 03:35 PM   #1
Raakh5
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Registered: Mar 2012
Posts: 167

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Changing .sh file dynamically


Hello,

I have written a servlet that moves specific amounts of file from 0* folder to * folder (01 to 1) and process these files. I made a .sh file and inserted in cron task to run it after every one hour.

There are 12 folder on location of my server /home/savedCVs/ i.e.
01
02
03
04
05
06
1
2
3
4
5
6

My .sh file:
Code:
wget -q "http://www.myDomain.com/servlet/Variable?category=1&folderId=01&noOfFiles=212"
/*
category=1 is destination foldername
folderId=01 is source folder name
*/
Can I refine my .sh file that when 0* folder (say 01) became empty then change category=2 and folderId=02 and so forth and so on and when 06 become empty then stop ths shell process?

Thanks in anticipation
 
Old 03-26-2012, 08:01 AM   #2
jhwilliams
Senior Member
 
Registered: Apr 2007
Location: Portland, OR
Distribution: Debian, Android, LFS
Posts: 1,168

Rep: Reputation: 210Reputation: 210Reputation: 210
You could use something based on find's -empty flag.

For example,

Code:
dir_number=1

if [ -z "$(find ${dir_number}/ -maxdepth 0 -type d -empty)" ]; then
    # The directory is empty
    # Do stuff here, then
    # Move to the next directory.
    $((dir_number++))
else
    # The directory has contents, do stuff here.
fi

Last edited by jhwilliams; 03-26-2012 at 08:04 AM.
 
1 members found this post helpful.
Old 04-01-2012, 04:47 PM   #3
Raakh5
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Registered: Mar 2012
Posts: 167

Original Poster
Rep: Reputation: Disabled
Thanks a lot
Best regards
 
  


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