Bash shell script problems need help ASAP!

chumpp · 03-16-2012, 01:09 AM

Thanks for the help!!

druuna · 03-16-2012, 02:16 AM

Hi,

The date command can do what you want/need:

Code:

date '+%l' -d 23
11

If you also need the am/pm string:

Code:

date '+%l %p' -d 23
11 PM

See man date for details.

BTW:
- please use [code]...[/code] around your code.
- Do not use ASAP. It might be urgent for you, but it sure isn't for us. We are volunteers.

Hope this helps.

chumpp · 03-16-2012, 08:57 AM

Thanks so much Druuna

druuna · 03-16-2012, 11:24 AM

Hi,

Quote:

Originally Posted by chumpp

I'm still kinda lost so should i do

Code:

date '+%l' -d 23

when i put the code in it just turned all the time to 11.

Yes, it is an example with a fixed time (23). Substitute 23 with the actual time you want to use.

It seems that this line stores your time value:

Code:

time=`grep $day p2.input2|cut -d " " -f 2`

You could do something like this:

Code:

fulltime=`grep $day p2.input2|cut -d " " -f 2`
time=$(date '+%l' -d ${fulltime})

All this can probably done more elegant and resource friendly, but with the info given I cannot help in that respect.

Hope this helps.

chumpp · 03-16-2012, 04:04 PM

Quote:

Originally Posted by druuna

Hi,
Yes, it is an example with a fixed time (23). Substitute 23 with the actual time you want to use.

It seems that this line stores your time value:

Code:

time=`grep $day p2.input2|cut -d " " -f 2`

You could do something like this:

Code:

fulltime=`grep $day p2.input2|cut -d " " -f 2`
time=$(date '+%l' -d ${fulltime})

All this can probably done more elegant and resource friendly, but with the info given I cannot help in that respect.

Hope this helps.

ah ok see i tried that but i did it like this time=$(date '+%l' -d {$fulltime}) and it wouldn't work i see how i did not need the $. Thanks so much for your help!