Bash Scripting

tkinsella · 02-07-2013, 04:16 PM

Hey All, I am trying to take user input and write it inside a file I am creating but I keep running into issues. Thoughts on another way to go about this?

Code:

read -p "Enter Text : " user1

cat >>/tmp/someFile.php <<'EOF'
<?PHP
/$var 1 = $user1
?>
EOF

However when I open the file it is displaying exactly what is above.

Thanks for your Help!!!

Ser Olmy · 02-07-2013, 04:25 PM

I believe the single quotes around EOF causes everything between that line and EOF to be interpreted literally (without variable expansion).

Try changing line 3 to:

Code:

cat >>/tmp/someFile.php <<EOF

You will also need to escape the first $ in line 5 to keep $var from being expanded to the contents of the (potentially non-existent) variable "$var".

ted_chou12 · 02-07-2013, 04:31 PM

Does this give you want you want?

Code:

read -p "Enter Text : " user1

echo "<?php 
\$var1 = \"$user1\";
?>" > "test.php"

cbtshare · 02-08-2013, 12:02 AM

this is what you want:

Quote:

#!/bin/bash

read -p "Enter Text : " user1

cat << EOF > try.txt

<?PHP
\$var 1 = $user1
?>
EOF

shivaa · 02-08-2013, 12:37 AM

Why making it complicated? It can be done without using cat, EOF and all that stuff, like:-

Code:

#!/bin/bash
read -p "Enter Text : " user1
echo $user1 >> /tmp/someFile.php

In addition, if you get any error in a script, add set for debugging, so when you invoke script, it can show execution of each line and any error(s).

Code:

#!/bin/bash
set -xv
(Rest script)

cbtshare · 02-08-2013, 08:08 AM

[QUOTE=shivaa;4886797]Why making it complicated? It can be done without using cat, EOF and all that stuff, like:-

Code:

#!/bin/bash
read -p "Enter Text : " user1
echo $user1 >> /tmp/someFile.php

This doesnt do what the OP wants,re-read the question

shivaa · 02-08-2013, 08:16 AM

Quote:

Originally Posted by tkinsella

Hey All, I am trying to take user input and write it inside a file I am creating but I keep running into issues. Thoughts on another way to go about this?

@cbtshare:
What other sense does it make?

cbtshare · 02-08-2013, 09:19 PM

you left this part out

Quote:

<?PHP
\$var 1 = $user1
?>

shivaa · 02-09-2013, 02:06 AM

Quote:

Originally Posted by cbtshare

you left this part out

Alright. I don't know what this part is. But initially I though that OP wanted to take input from user only once and write it to a file.

Anyway, if OP wants to take input repeatedly, then a loop can do that like:-

Code:

#!/bin/bash
while true
do
read -p "Enter some text: " text
echo $text >> /path/to/outputfile.txt
done

And use CTRL+C to exit from it.