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Old 06-26-2003, 03:55 PM   #1
brian0918
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bash scripting question


I need to look for files of a certain name (such as: bleh*.*) within a directory and its subdirectories, and if any files have that sort of name (eg: bleh123.out), I need to have those filenames (just the filenames) printed out, one per line. How can that be done?

Thanks.
 
Old 06-26-2003, 03:56 PM   #2
david_ross
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Why not just use find?
 
Old 06-26-2003, 03:58 PM   #3
brian0918
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Quote:
Originally posted by david_ross
Why not just use find?
But what would I use to have it only print the filenames?

if you use:

find . -name 'bleh*.*'

it prints out the directory structure.
 
Old 06-26-2003, 04:01 PM   #4
david_ross
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Use the print format:
find /path/to/smoewhere -name blah*.* -printf "%f\n"
 
Old 06-26-2003, 04:03 PM   #5
brian0918
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Thanks.
 
Old 06-26-2003, 04:22 PM   #6
brian0918
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Is there a way to have it only print everything up to the decimal point in the filename?
So if it finds bleh123.321, it prints out:

bleh123
 
Old 06-26-2003, 04:44 PM   #7
david_ross
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There is no print format to do that. The only way I can think of is to use awk. I'm not great with awk but this should work:
Code:
find /path/to/somewhere -name blah*.* -printf "%f\n" | awk -F. '{print $1}'
 
Old 06-26-2003, 04:48 PM   #8
brian0918
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Quote:
Originally posted by david_ross
There is no print format to do that. The only way I can think of is to use awk. I'm not great with awk but this should work:
Code:
find /path/to/somewhere -name blah*.* -printf "%f\n" | awk -F. '{print $1}'
Thanks, it works.
 
  


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