Bash script problem
 

Hello,

I am writing a bash script which uses the find command and stores the result of the find command to a variable. How do I retreive the values present in the variable one by one?

ie:
#!/bin/sh

VAR=`find /home/par_dir -type f -name "target_file" -print`
(The result of the find command is:
/home/par_dir/abc/target_file
/home/par_dir/xyz/target_file
)

Now, when I use
for linee in VAR
do
echo $linee
done

I am not able to retreive the rows one by one.
Can anybody help me in doing so?

Thanks in advance..!!

Regards,
Harish

Best way to go, IMO, is using an array for this. Have a look here - http://stackoverflow.com/questions/1...o-a-bash-array

Cheers,

Josh

You'll find just about everything you need to know here:

http://mywiki.wooledge.org/BashFAQ/001


I recommend using a loop to set the files into an array instead of a scalar variable.

Technically, either way would work. Besides, that's what I meant by giving that link to the OP. Maybe you were looking at something different on that page?

I was just reiterating what you said, really, while adding another link with a slightly broader focus than yours, and a scripting example.

We agree that arrays are the way to go here, certainly. Any time you have a list of related strings, such as file names, you should be using an array for it.

More help on arrays here:
http://mywiki.wooledge.org/BashGuide/Arrays
http://www.tldp.org/LDP/abs/html/arrays.html