[SOLVED] Bash script

gregmcc · 08-06-2013, 06:16 AM

For some reason i am struggling with the following.

I have a command that greps out data from a text file:

Code:

cat file | grep Registration | awk '{print $3}'

This prints out:
10
11
22
32

I want to check if any of the values = 100 and then echo "Error"

I know I need to use a for loop but then how do I specify the number of times to loop, and if I put the grep in the loop wont it only spit out the first match each time?

druuna · 08-06-2013, 06:27 AM

Is this what you are looking for:

Code:

 awk '/Registration/ { if ( $3 == "100" ) { print $3, "error" } else { print $3 } }' infile

Example run:

Code:

$ cat infile
Registration blaat 10
Registration foobar 11
Registration foo 100
Registration bar 22
Registration bar 32

$ awk '/Registration/ { if ( $3 == "100" ) { print $3, "error" } else { print $3 } }' infile 
10
11
100 error
22
32

gregmcc · 08-06-2013, 06:33 AM

Thanks a lot! Perfect!