LinuxQuestions.org - [SOLVED] Bash: Reading file into array

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Bash: Reading file into array

Assume I have a file named file.txt with the following contents

Code:

19 man

24 house

44 dyam

90 random

I want to read the file into array and store each line in each index. I've tried using the following code.

Code:

dataarray=($( < file.txt ))

It stores each word in each index rather than each line in each index.
Can someone please help me.

www.google.com/linux is your friend for anything GNU/Linux/Unix. I entered search terms "bash array input" and found this: http://www.linuxconfig.org/Bash_scripting_Tutorial. Scroll down to "8.2. Read file into bash array".

Naturally it is much less elegant than what you started with,
but you could always force bash to do what you want like this:

Code:

# Just to be formal, declare the array.

declare -a data_array







# Force reading of each line into one element of the array.



line_cnt=0



while :

    do



        read data_line



        if [ $? -ne 0 ]

            then

                break

        fi



        data_array[$line_cnt]="$data_line"



        (( line_cnt++ ))



    done  <  file.txt









# To verify one line per element, display the contents of one element per line.



line_num=0



while [  $line_num  -lt  $line_cnt  ]

    do



        echo "data_array[$line_num]=${data_array[$line_num]}"



        (( line_num++ ))



done

Well I would think the simple loop would be fine:

Code:

while read -r line; do arr+=( "$line" ); done<file