Bash infinite loop problem haunting

stp001 · 03-17-2010, 06:14 PM

Hi
I want to figure out what is going on in this small script.Its really strange.I think its the infinite loop again.All I want to do is to collect some data from the zenity dialog box in an array and then echo it.
Here is the code

Code:

#!/bin/bash
#export PS4='+${BASH_SOURCE}:${LINENO}:${FUNCNAME[0]}: ' debugging info

IFS_OLD= $IFS
#IFS=':' 
result



function pageInfo {

local num
 arr_local

 for (( i=0 ; i<5 ; i++ ))
  do
	while true

           test_param= $(zenity --entry --text "Please enter $param  for the webpage")
	      
           if [[  -n "$test_param"  && "$?" -eq  0  ]] ; then
	       arr_local["$num"]=$test_param 
                        (( num++ ))
		break             
	   fi

	  done
     
 done	
  echo ${arr_local[@]}      
	
}

result=(`pageinfo`)
echo "$result"
#EOF

Thanks

smoker · 03-17-2010, 06:22 PM

Is $num null or zero ?

colucix · 03-17-2010, 06:22 PM

You did not provide many details about what you got from running this script (error messages, unpredictable results and so on). Anyway, two syntax errors come at first sight:

Code:

IFS_OLD= $IFS

and

Code:

test_param= $(zenity --entry --text "Please enter $param  for the webpage")

In assignments there must not be extra spaces around the equal sign. It should be:

Code:

test_param=$(command)

chrism01 · 03-17-2010, 06:29 PM

Also, you don't call fn that way

Code:

result=(`pageinfo`)

should be

result=pageInfo

note also you spelled the fn name wrong

Try running with

Code:

#!/bin/bash

# This line shows what bash is really doing
set -xv

pixellany · 03-17-2010, 06:32 PM

Two nits:

--You don't say exactly what is (or is not) happening.

--You can add echo statements to check on what is happening in different parts of the script.

smoker · 03-17-2010, 06:43 PM

I don't see how an uninitialised variable can be used as an index in an array.
If I run

Code:

echo "$num"
((num++))
echo "$num"

I get

Code:

user@shell>

1

So arr_local["$num"]=$test_param has no index.

Wouldn't $i be more useful there ?