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touch a b a\(c\)b
$ ls *\(c\)*
a(c)b
$ for a in *\(c\)*; do ls $a; done
a(c)b
# this is ok
rm a\(c\)b
$ ls *\(c\)*
ls: cannot access *(c)*: No such file or directory
$ for a in *\(c\)*; do ls $a; done
a b
# this is not clear. please tell me why would this happen?!
Yes it does, thank you for your answer.
Why would be ls inconsistent with for, and why would *\(c\)* expand to the list of files as one word? I should be able to understand it by myself starting from here.
Put quotes around your variable in the for loop, same as you would if there's a space or any other "bad" character.
Code:
$ touch a b
for a in *\(c\)*; do ls $a; done
a b
$ for a in *\(c\)*; do ls "$a"; done
ls: cannot access *(c)*: No such file or directory
same as this
Code:
$ touch "a b"
$ ls *\ *
a b
$ for a in *\ *; do ls $a; done
ls: cannot access a: No such file or directory
ls: cannot access b: No such file or directory
$ for a in *\ *; do ls "$a"; done
a b
If there's ever a chance you're going to have a character that requires delimiting (-, (, space, etc.) stored inside a variable, then you need to stick quotes around it when you use it.
Last edited by suicidaleggroll; 12-17-2014 at 04:42 PM.
Sorry to bother you again, but please tell me why does this happen. () should introduce some subshell which here should result in an error.
Code:
$ ls *()*
a a(c)b a(c)c b
$ ls *()
ls: cannot access *(): No such file or directory
$ ls ()*
bash: syntax error near unexpected token `('
$
OK, so *() is some pattern matching in pathname expansion. So bash is looking for some file with a void name? OK, so nothing matches nothing, that's right. I did fall into a succession of traps here, did I not? Thank you all,
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