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The main problem is that i don't have experience with Bash and i don't have time to practice...
Actually you must spend some time reading the manual pages and a good tutorial (for example http://rute.2038bug.com/index.html.gz). The solution to your problem is written in the question itself: "Write a script that finds...". Read the manual page of the find command
looking for the needed options under the "TEST" section.
This, running from the top of the directory tree should be okay imo. Is it right?
Just try that and... read the error messages (if any) or see if the output matches exactly what you're trying to do. Since the problem is to find files older than... you have to use -mtime, since -atime look at the last access time, whereas the last modification time gives the actual age of the file.
Furthermore, you cannot do multiplication using the asterisk, since it has a special meaning in bash (is up to you to find out what it means).
Almost there. The multiplication can be done in different ways:
let n="$1 * 7"
n=$(($1 * 7))
n=$(expr $1 \* 7)
the last one uses command substitution $(command) where the command to do arithmetics is expr. Note that the multiplication sign must be escaped using a backslash in this case.
Also, follow the advice by druuna in post #7 otherwise the -mtime and -size tests match only the exact values. Use the + sign for -mtime to match files "older than" and the + sign for -size to find files "bigger than".