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Old 01-07-2010, 04:35 AM   #1
john83reuben
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Registered: Oct 2007
Location: Kuala Lumpur,Malaysia
Distribution: Debian Etch, OpenSuse
Posts: 132

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awk problem


i did the following script

Code:
echo Every good boy is bad boy | awk '{first=substr($0,1,2)}{second=substr($0,8)}{printf("%s%s\n",first,second)}'
The result is Evood boy is bad boy

How to get the following result

Evood boy is baoy (substr the d,<space> and b)

when i try this

Code:
echo Every good boy is bad boy| awk '{first=substr($0,1,2)}{second=substr($0,8)}{third=substr($5,1,2)}{fourth=substr($6,2)}{printf("%s%s%s%s\n",first,second,third,fourth)}'
im getting this

Evood boy is bad boybaoy

Please advice

Thanks

Jo
 
Old 01-07-2010, 06:43 AM   #2
stefansbv
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Registered: May 2009
Distribution: Slackware
Posts: 17
Blog Entries: 1

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This works, (if not then it's a cut and paste problem from my side).

Code:
echo Every good boy is bad boy | awk '{first=substr($0,1,2);second=substr($0,7,4);third=substr($0,11,10);fourth=substr($0,24,2);}END{printf("%s%s%s%s\n",first,second,third,fourth)}'
The first 'substr' function returns 2 chars from string, starting at position 0, just to be clear, 'substr' doesn't delete chars from the string. To get what you want you have to extract and concatenate the desired chars from the strings.
 
  


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