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Old 04-02-2013, 04:18 PM   #1
dmesserly
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Registered: Apr 2013
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AWK - Linux vs Unix?


I am relatively new to Linux, but have worked on Solaris Unix for 15+ years. On an Ubuntu 12.04 system, I have written a very simple AWK script which continues to throw errors. By very simple I mean "pattern {action}" with just a few lines. I can't figure this out, unless there is a difference with AWK on Linux vs. Unix. But even that does not seem like there should be any issues. Below is the script & errors. Can you see any problems with this script?
donald$ cat PSA.awk
{
/#0/ { printf("%s %s", $2, $3) }
/#1 AT/ { printf(",%s\n", $4) }
/#1 EMA/ { printf(",%s\n", $3) }
/\// { next }
}
donald$ awk -f PSA.awk $HOME/Documents/SCACL.txt
awk: PSA.awk:2: /#0/ { printf("%s %s", $2, $3) }
awk: PSA.awk:2: ^ syntax error
awk: PSA.awk:3: /#1 AT/ { printf(",%s\n", $4) }
awk: PSA.awk:3: ^ syntax error
awk: PSA.awk:4: /#1 EMA/ { printf(",%s\n", $3) }
awk: PSA.awk:4: ^ syntax error
awk: PSA.awk:5: /\// { next }
awk: PSA.awk:5: ^ syntax error
 
Old 04-02-2013, 04:36 PM   #2
rknichols
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Quote:
Originally Posted by dmesserly View Post
Below is the script & errors. Can you see any problems with this script?
donald
Code:
$ cat PSA.awk
{ 
   /#0/     { printf("%s %s", $2, $3) }
   /#1 AT/  { printf(",%s\n", $4) }
   /#1 EMA/ { printf(",%s\n", $3) }
   /\//     { next }
}
donald$ awk -f PSA.awk $HOME/Documents/SCACL.txt
awk: PSA.awk:2:    /#0/     { printf("%s %s", $2, $3) }
awk: PSA.awk:2:             ^ syntax error
awk: PSA.awk:3:    /#1 AT/  { printf(",%s\n", $4) }
awk: PSA.awk:3:             ^ syntax error
awk: PSA.awk:4:    /#1 EMA/ { printf(",%s\n", $3) }
awk: PSA.awk:4:             ^ syntax error
awk: PSA.awk:5:    /\//     { next }
awk: PSA.awk:5:             ^ syntax error
Get rid of those extraneous braces. awk is trying to interpret everything within those braces as an action statement (with a null pattern that matches every line).
 
Old 04-02-2013, 04:52 PM   #3
dmesserly
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Registered: Apr 2013
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I tried that and it just moves the syntax error over...
donald$ cat PSA.awk
{
/#0/ printf("%s %s", $2, $3)
/#1 AT/ printf(",%s\n", $4)
/#1 EMA/ printf(",%s\n", $3)
/\// next
}
donald$ awk -f PSA.awk $HOME/Documents/SCACL.txt
awk: PSA.awk:2: /#0/ printf("%s %s", $2, $3)
awk: PSA.awk:2: ^ syntax error
awk: PSA.awk:3: /#1 AT/ printf(",%s\n", $4)
awk: PSA.awk:3: ^ syntax error
awk: PSA.awk:4: /#1 EMA/ printf(",%s\n", $3)
awk: PSA.awk:4: ^ syntax error
awk: PSA.awk:5: /\// next
awk: PSA.awk:5: ^ syntax error
donald$
 
Old 04-02-2013, 05:08 PM   #4
dmesserly
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Registered: Apr 2013
Posts: 6

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Rknichols

Ignore that previous post. I re-read your post and realized which braces you were referring to. I'm now getting data from the script. Thanks!
 
Old 04-03-2013, 01:57 AM   #5
grail
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Remember to mark as SOLVED once you have your solution
 
  


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