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Old 01-11-2010, 10:06 AM   #1
rhinoict
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awk ?


I have a .out file that has this information:
-rw-r--r-- 1 root system 1763444 Sep 30 18:11 log.td-ict-111

I just want a simple script to list only the last row of informatin (the log. names) How can I do this with awk?
 
Old 01-11-2010, 10:25 AM   #2
TB0ne
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Quote:
Originally Posted by rhinoict View Post
I have a .out file that has this information:
-rw-r--r-- 1 root system 1763444 Sep 30 18:11 log.td-ict-111

I just want a simple script to list only the last row of informatin (the log. names) How can I do this with awk?
The man page for awk has all the options on it, and Google's got lots of examples, if you looked.

Awk, by default, splits things on white-space. So if you put your string into it, you want to print out field 9, based on your example.
Code:
awk '{print $9}'
 
Old 01-11-2010, 10:37 AM   #3
SethsdadtheLinuxer
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here's a nifty link
http://forums13.itrc.hp.com/service/...readId=1154641
the awk one-liner
awk 'END {print}' file
sed '$!d' file (- bonus)
 
Old 01-11-2010, 10:40 AM   #4
cpplinux
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NF means number of fields in awk. You can use $NF to refer to the last field.
Code:
awk '{print $NF}' myfile.out
Edit: Sorry, I thought you meant the last column. For the last row, go for SethsdadtheLinuxer's solution.

Last edited by cpplinux; 01-11-2010 at 10:44 AM.
 
Old 01-11-2010, 11:46 AM   #5
vrmartin2
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Why not use tail?

Just curious: Why use awk when you can use "tail -1 <file>"?
 
Old 01-11-2010, 11:49 AM   #6
pixellany
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Quote:
Originally Posted by vrmartin2 View Post
Just curious: Why use awk when you can use "tail -1 <file>"?
Almost certainly, because he/she meant columns and not rows.
 
Old 01-11-2010, 12:29 PM   #7
rhinoict
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pixellany was correct I was needing the last column of data from the .out file. The command that cpplinux suggested (awk '{print $NF}' myfile.out) worked perfectly in my applicaion.
Thanks to all for the help
 
  


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