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Can you please explain me what the above commands doing.
It does exactly what you were trying to achieve in your awk code. But it is the correct way to do. You used a shell-like command substitution with backticks, instead the awk's "command substitution" actually uses getline in the form:
"shell command here" | getline varname
so that the output of the shell command will be stored in varname which can be used later inside awk. It's all explained in the link I posted above.
However, this is a GNU awk extension. If you're not running it on a Linux machine, most likely it will fail. Better the sed solution without the -i option.
If you dont mind, i tried below command to get date in required format. didnt work.
sed "s/$/;$(date "+%d/%m/%Y")/"
Always consider the quotes in pair: the problem is the first double quote before + closes the quote at the beginning, the other one opens a new pair of quote together with the ending one. Moreover the replacement string (that is the shell command) contains slashes: this confuses sed, that doesn't understand where the / delimiter really is. In this case you can avoid the double quotes to embed the date format and you can use another delimiter for the s command: