[SOLVED] Accessing arrays position in a split string

xeon123 · 03-10-2011, 09:12 AM

Hi,

I've a string "this.is.a.name", and I would like to put it in an array.
But, I've like to print the output of the array as:

Code:

echo ${array[0]}
echo ${array[1]}
echo ${array[2]}
echo ${array[3]}

I've tried with

Code:

STR="this.is.a.name";
arr=$(echo $STR | tr "." " ");

echo ${array[0]}
echo ${array[1]}
echo ${array[2]}
echo ${array[3]}

but only the first position contains the phrase "this is a name". The rest of the array is empty.

I've searched over the manuals and the web, and I couldn't find a solution for my case.

How can I do that?

Thanks,

Guttorm · 03-10-2011, 09:18 AM

You're close, but you need to add another set of () when you assign the array.

Code:

#!/bin/bash
STR="this.is.a.name"
array=($(echo $STR | tr "." " "))
echo ${array[0]}
echo ${array[1]}
echo ${array[2]}
echo ${array[3]}

xeon123 · 03-10-2011, 09:20 AM

That's right Guttorm, but what's the meaning of the outer parenthesis of "($(echo $STR | tr "." " "))"?

Guttorm · 03-10-2011, 09:25 AM

Without the outer, the variable named array simply gets the value of "this is a name". The outer means it will be an array. The difference is the same as

array="this is a name"
array=(this is a name)

xeon123 · 03-10-2011, 09:36 AM

Now I get it. Thanks for the help.