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Old 11-02-2009, 06:17 AM   #1
bioinformatics_guy
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Registered: Aug 2008
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Absolute Value function in AWK


I was wondering if there was an absolute value function in awk? More specifically, I need it in a string of boolean operators.

Right now I have:

awk '{ if ( $1 == 0 && $2 != $1 && [absolute value of $1-$2] <= 6 ) print }'

But I don't know what I need to put in the brackets.
 
Old 11-02-2009, 06:31 AM   #2
bioinformatics_guy
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I figured it out, but in case anyone was interested or has a similar problem, the line is:

awk '{ if ( $1 == 0 && $2 != $1 && ( $1-$2 >=0 ? $1=$2 : $2-$1 ) <= 6 ) print }'
 
Old 11-02-2009, 06:50 AM   #3
geek.ksa
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Ummm one could implement an absoluteness function by simply:

function abs(value)
{
if(value < 0)
return value * -1
else
return value
}

didn't test it but it should work :P
 
Old 11-02-2009, 07:05 AM   #4
jlliagre
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That might be simplified to:
Code:
function abs(value)
{
  return (value<0?-value:value);
}
 
  


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