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Old 07-13-2004, 09:55 PM   #1
kingsyl
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Registered: Jul 2004
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A strange bash script


#!/bin/sh
.............
head -n file > ! pp


What does this line mean ? I am puzzled...
 
Old 07-13-2004, 10:55 PM   #2
ranger_nemo
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Registered: Feb 2003
Location: N'rn WI -- USA
Distribution: Kubuntu 8.04, ClarkConnect 4
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Well, I can break it down a bit...

"head" prints out (usually) the first ten lines of a file. So, "head file1" would print the ten lines in the file named file1. You can modify the number of lines printed with "-n #". "head -n 22 file1" would print out the first 22 lines of the file named file1. Your script line seems to be missing the # after -n.

The ">" redirects the output of the command before it. If takes the output of the head command and sends it somewhere other than the screen. It's usually to a file. "head -n 22 file > file2" would write the first 22 lines of the file named file1 into the file named file2.

I don't know what the exclamation mark is for... It's usually used as a "not" in a conditional when you are comparing two items. "if a != b" means "if a does not equal b". Although in Bash it would be "if [a -ne b];". It prob'ly means something in the Bourne shell. The first line, "#!/bin/sh", calls the Bourne shell. If it was calling Bash, it would be "#!/bin/bash".

The pp might be another program or script that is using the print out from head, or it might be a file that the print out is going into.
 
Old 07-13-2004, 11:07 PM   #3
homey
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Registered: Oct 2003
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Well it does seem a bit strange just seeing part of it. The number of lines to be displayed is missing where it should be -n 5 or some other number. The output of head is redirected to !pp and !pp is the last command in history which started with pp

So it would look like this... head -n 5 somefile > !pp
 
  


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