I use getaddrinfo to get the ip address of the server, it works well on other 3 machines, but always get local address 127.0.0.1 on an 64 bit linux machine. Therefore, other remote clients can not connect to the socket server because the server binds local address l27.0.0.1.

I have also tried pass 0.0.0.0 to getaddrinfo, now the server bind on 0.0.0.0(all available interface). But now I can not print the correct network address of the server, as it is always 0.0.0.0 which is provided by getsockname.

I do not know how to get the network address of the server, rather than the local address. Can anyone help me out? Thanks a lot.

This probably would get better attention and the right kind of attention in the programming forums.

Without having a look at the relevant pieces of code to determine what might be going wrong, it's really hard to say what the specific problem is or maybe.

Network address belongs to NIC or NIC, just type from root console:
ifconfig -a

And you will see.

Thanks for your reply,

To make things clear,

A linux machine may have multiple ip address, for example,

127.0.0.1 (local ip address)
198.12.1.12 (external address)

if there a c function like getaddrinfo(..) which can get the external address(198.12.1.12), rather than the local address(127.0.0.1)?

ifconfig -a

Yes, but I want to get the address by c program. Thanks.

You can parse output with perl for example.

But may be someone else here gives you a better solution.

To be honest I'd suggest posting how you're currently getting the ip address, hard to guess what you may or may not be doing correctly without seeing the code itself. Because it works on one particular subset of machines does not mean its portable or correct.