Quote:
Originally Posted by rbeserie
"ps -A u" gives me the list of all
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Please use CODE tags instead of QUOTE tags for things like that. It makes a big difference in readability.
Quote:
Originally Posted by AlucardZero
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Cute picture at the top, and a good newbie level answer to the question.
Quote:
Originally Posted by rbeserie
if i sum it all up I get a big 16% mem usage...
if my math is all right, 16% of 2048 is 327.
so the free mem should be : 2048 - 327 and that is : 1697MB.
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Adding up the %MEM column and multiplying by total memory, is just an inaccurate way (accumulates rounding errors) of totaling the RSS column.
The total of RSS is itself a fairly bad estimate of the total memory used by all those processes (a better estimate that you get from %MEM, but still fairly bad).
So far as I know, there isn't a better estimate of that total, other than getting it from the other side (which defeats the purpose of comparing it to the other side): From the total subtract kernel memory use, cache, buffers, and free. I think the result would be the true value of what you might expect the total of RSS to represent.