Ultra Basic script...

MasterC · 04-22-2003, 10:56 PM

Hi, I have a few applications that I run with ALOT of flags, I am thinking I could run these applications with a very simple/basic script, but am not sure if it'd work right, here's an example of what I am thinking would work:

Code:

!#/bin/bash
application --this-flag of 10 \
--this-flag of 10 --this flag of 10 \
--this-flag of 10 --this-one-also \
--and-so on --and-so on

A more "real" example:

Code:

#!/bin/bash
mencoder -alang en -dvd 1 -ovc lavc -lavcopts vcodec=mpeg4:vhq:vbitrate=1200:vme=5 \
-vop scale -zoom -xy 512 \
-oac mp3lame -lameopts abr:br=160 \
-o /home/masterc/movies/DVD.avi

For DVD ripping. If that would work, is my syntax correct? And then to execute it, would I simply:
./mendvd

Assuming I'm in the directory containing the script, and I've titled it mendvd?

Thanks for any suggestions, bagerings, and blatent attacks

Cool

Tinkster · 04-22-2003, 11:31 PM

Of course it would mate, how could you have
ANY doubt? ;)

Cheers,
Tink

MasterC · 04-23-2003, 12:00 AM

Cool, thanks for the re-assurance tink

DavidPhillips · 04-23-2003, 10:22 AM

cool

you could also put $1 in the place of DVD and then use it like this

mendvd nameofmovie