turn off event designator without recompiling the bash

Fle>< · 11-10-2006, 08:54 AM

hi, my problem is a command like that:

Quote:

iptables -A INPUT -s 127.0.0.1 -d !127.0.0.1 -j REJECT

The bash substitutes !127 with a command from the history, and so the iptables command doesn't work.

Is there a way to turn this behavior off without recompiling the shell and disable the option "-enable-bang-history"? What is an alternative to write iptables commands like my own?

matthewg42 · 11-10-2006, 09:14 AM

You can escape the ! with a backslash, \, like this:

Code:

iptables -A INPUT -s 127.0.0.1 -d \!127.0.0.1 -j REJECT

You can also quote the parameter which includes the ! in single quotes (note NOT backticks!):

Code:

iptables -A INPUT -s 127.0.0.1 -d '!127.0.0.1' -j REJECT

Fle>< · 11-10-2006, 09:42 AM

I think I tried that already... but I am not sure so I will give it a try (again) in the evening (have no possibility now).

Fle>< · 11-10-2006, 04:25 PM

No, this do not work:

Quote:

# iptables -A INPUT -s 127.0.0.1 -d '!127.0.0.1' -j REJECT

# iptables -A INPUT -s 127.0.0.1 -d \!127.0.0.1 -j REJECT

after pressing enter the cursor jumps into the next line and waits...and waits... and nothing happens (until ctrl + c)

matthewg42 · 11-10-2006, 05:22 PM

Well that's how to prevent the shell from interpreting the ! as an event. I don't know about iptables.

Fle>< · 11-10-2006, 05:32 PM

you're right, that was an iptables fault.
problem solved, thanks a lot.