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12-01-2010, 02:09 PM
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#1
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Member
Registered: Oct 2009
Posts: 116
Rep:
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syntax error near unexpected token `else'
I wrote a script to start portal.
Its start portal (not a problem)
Only getting following message:
./WebPortaltest.sh: line 56: syntax error near unexpected token `else'
./WebPortaltest.sh: line 56: `else'
This is the else before second logic
{/}
#
else
if [ "$host" == "prd6" ] || [ "$host" == "stg6" ] ||
[ "$host" == "wprd6" ] || [ "$host" == "tst6" ]; {/}
Here is the whole script:
{/}
#------------------> web_portal_start.sh <-------------------#
# #
# Modification log #
# ---------------- #
# #
# ------Please add new entries at the top. Be proud #
# | of your work. Comment it! #
# V #
# DATE WHO DESCRIPTION #
# ---- --- ----------- #
# 01/12/10 tst initial release to start portal #
# #
#-------------------------------------------------------------#
#!/bin/bash
set -x
host=$(hostname);
dt=$(date +'%D %T')
logfile='PortalUp.log'
profile_path='/opt/IBM/WebSphere/wp_profile'
#
#--> Determine which portal to use based on host name <--
#--> set portal1 for host name prd5, stg5, <--
# wprd5, tst5, <--
# wstg5 or dev2 <--
#
#--> set portal2 for host name prd6, stg6, <--
# wprd6, or tst6 <--
#
#portal_start='null';
#
if [ "$host" == "prd5" ] || [ "$host" == "stg5" ] ||
[ "$host" == "wprd5" ] || [ "$host" == "tst5" ] ||
[ "$host" == "wstg5" ] || [ "$host" == "dev2" ];
then
su -l admin -c /home/admin/scripts_PS/startportal & >> /tmp/weblog/$logfile
echo $dt start command for $server_name on $host Server has been issued. >> /tmp/weblog/$logfile
fi
# check every 3 minutes to see if server has been started. if server does not start in 30 minutes (10 checks), exit the script with
# return code 8
let "count = 0"
while [ $count -lt 11 ]
do
let "count = count +1"
#
dt=$(date +'%D %T')
#
if [ -f $profile_path/logs/$server_name/$server_name.pid ]; then
echo $dt $server_name on $host server has been successfully started. >> /tmp/weblog/$logfile
exit
#
else
echo $dt start process for $server_name on $host server is still running. checked $count times, 3 minutes apart >> /tmp/weblog/$logfile
sleep 180
fi
#
else
if [ "$host" == "prd6" ] || [ "$host" == "stg6" ] ||
[ "$host" == "wprd6" ] || [ "$host" == "tst6" ];
then
su -l admin -c /home/admin/scripts_PS/startportal_2 & >> /tmp/weblog/$logfile
echo $dt start command for $server_name on $host Server has been issued. >> /tmp/weblog/$logfile
fi
# check every 3 minutes to see if server has been started. if server does not start in 30 minutes (10 checks), exit the script with
# return code 8
let "count = 0"
while [ $count -lt 11 ]
do
let "count = count +1"
#
dt=$(date +'%D %T')
#
if [ -f $profile_path/logs/$server_name/$server_name.pid ]; then
echo $dt $server_name on $host server has been successfully started. >> /tmp/weblog/$logfile
exit
#
else
echo $dt start process for $server_name on $host server is still running. checked $count times, 3 minutes apart >> /tmp/weblog/$logfile
sleep 180
fi
done
#
dt=$(date +'%D %T')
echo $dt start process for $server_name on $host server DID NOT complete successfully. checked $count times, 3 minutes apart >> /tmp/weblog/$logfile
exit 8
#
{\}
Thanks
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12-01-2010, 02:18 PM
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#2
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Moderator
Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.4 OpenSuSE 12.2
Posts: 9,899
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There is no if before the else at line 56:
Code:
47 if [ -f $profile_path/logs/$server_name/$server_name.pid ]; then
48 echo $dt $server_name on $host server has been successfully started. >> /tmp/weblog/$logfile
49 exit
50 #
51 else
52 echo $dt start process for $server_name on $host server is still running. checked $count times, 3 minutes apart >> /tmp/weblog/$logfile
53 sleep 180
54 fi
55 #
56 else
57 if [ "$host" == "prd6" ] || [ "$host" == "stg6" ] ||
58 [ "$host" == "wprd6" ] || [ "$host" == "tst6" ];
59 then
60 su -l admin -c /home/admin/scripts_PS/startportal_2 & >> /tmp/weblog/$logfile
61 echo $dt start command for $server_name on $host Server has been issued. >> /tmp/weblog/$logfile
62 fi
If you want to put an "else if" condition the correct syntax is elif, as in
Code:
if expression
then
<commands>
elif expression
<commands>
fi
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12-01-2010, 03:27 PM
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#3
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Senior Member
Registered: Oct 2004
Distribution: Fedora Core 4, 12, 13, 14, 15, 17
Posts: 2,279
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It's amazing what proper indentation and code block markers can do.
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12-07-2010, 05:17 PM
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#4
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Member
Registered: Oct 2009
Posts: 116
Original Poster
Rep:
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I repalced else & if to elif
Still woks but now I am getting message as below:
./WebPortalDntest.sh: line 56: syntax error near unexpected token `elif'
./WebPortalDntest.sh: line 56: `elif'
Here is the script:
{/}
elif
[ "$host" == "prd6" ] || [ "$host" == "stg6" ] ||
[ "$host" == "wprd6" ] || [ "$host" == "tst6" ];
then
su -l admin -c /home/admin/scripts_PS/startportal_2 & >> /tmp/weblog/$logfile
{\}
Last edited by dnaqvi; 12-07-2010 at 09:56 PM.
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12-07-2010, 07:34 PM
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#5
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Senior Member
Registered: Jan 2010
Posts: 1,604
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Quote:
Originally Posted by dnaqvi
I repalced else & if to elif
Still woks but now I am getting message as below:
./WebPortalDntest.sh: line 56: syntax error near unexpected token `elif'
./WebPortalDntest.sh: line 56: `elif'
Here is the script:
{/}
elif
[ "$host" == "prd6" ] || [ "$host" == "stg6" ] ||
[ "$host" == "wprd6" ] || [ "$host" == "tst6" ];
then
su -l admin -c /home/admin/scripts_PS/startportal_2 & >> /tmp/weblog/$logfile
{/}
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Hi,
Colucix already gave you the answer. You do not have an if before your else. You cannot just start and else branch nor can you just start with an elif branch. Just remove the else completely in your previous script. This should fix the syntax. Not sure if the logic of your script is correct, though. Your script is unreadable. Please use code tags and reformat it properly.
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12-08-2010, 03:37 AM
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#6
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Moderator
Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.4 OpenSuSE 12.2
Posts: 9,899
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As crts said: the else or elif keyword is left alone. Check the sequence of control statements and eventually review the script's logic.
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