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Old 06-09-2004, 02:06 PM   #1
chrisk5527
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Subtracting dates


How can I subtract 2 days from 6/01/2004 and end up with 5/30/2004? I'm stuck.
 
Old 06-09-2004, 02:34 PM   #2
Nis
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Code:
date --date='2 days ago' +%D
Direct from the date info pages. Some utilites use info pages instead of man pages so if the man page doesn't seem helpful try 'info command'
 
Old 06-09-2004, 02:58 PM   #3
homey
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Maybe something along these lines..........

Code:
#!/bin/bash

then=`date +%B" "%d" "%Y -d "-2 day"`
now=`date +%B" "%d" "%Y`
tomorrow=`date +%B" "%d" "%Y -d "1 day"`


echo " Two days ago was $then"
echo " Todays date is $now"
echo " Tomorrows date is $tomorrow"
 
Old 06-10-2004, 02:02 PM   #4
chrisk5527
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What I have is a filename such as 06012004_TEST_TEST and I'm trying to figure out what the Sunday date would be. I've been able to parse the filename out into month, day and year. It would be May 30th 2004, but how would I figure that out in a shell script? Any ideas?
 
Old 06-10-2004, 02:23 PM   #5
jim mcnamara
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If you want to use shell scripts here is a resource for a lot of date shell code:

http://www.unix.com/showthread.php?s...ate+arithmetic
 
Old 06-10-2004, 03:07 PM   #6
chrisk5527
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Thanks for that, but Im not sure anything in there answered my question. What I'm looking for is how to determine the date with another date For example, I have a date 6/01/2004 and I want to know the date of the prior Sunday which would be 5/30/2004. Another example would be 6/10/2004, the Sunday date would be 6/6/2004.

I would like something like
Code:
 date --date="6/7/2004"  "1 day ago"
and have it display 6/6/2004

Thanks.
 
Old 06-10-2004, 03:57 PM   #7
chrisk5527
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I think I figured a solution out, but now I need to figure out how many days ago a date was. For example, 6/6/2004 was 4 days ago.

Last edited by chrisk5527; 06-10-2004 at 04:05 PM.
 
  


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