Subtracting dates

chrisk5527 · 06-09-2004, 01:06 PM

How can I subtract 2 days from 6/01/2004 and end up with 5/30/2004? I'm stuck.

Nis · 06-09-2004, 01:34 PM

Code:

date --date='2 days ago' +%D

Direct from the date info pages. Some utilites use info pages instead of man pages so if the man page doesn't seem helpful try 'info command'

homey · 06-09-2004, 01:58 PM

Maybe something along these lines..........

Code:

#!/bin/bash

then=`date +%B" "%d" "%Y -d "-2 day"`
now=`date +%B" "%d" "%Y`
tomorrow=`date +%B" "%d" "%Y -d "1 day"`


echo " Two days ago was $then"
echo " Todays date is $now"
echo " Tomorrows date is $tomorrow"

chrisk5527 · 06-10-2004, 01:02 PM

What I have is a filename such as 06012004_TEST_TEST and I'm trying to figure out what the Sunday date would be. I've been able to parse the filename out into month, day and year. It would be May 30th 2004, but how would I figure that out in a shell script? Any ideas?

jim mcnamara · 06-10-2004, 01:23 PM

If you want to use shell scripts here is a resource for a lot of date shell code:

http://www.unix.com/showthread.php?s...ate+arithmetic

chrisk5527 · 06-10-2004, 02:07 PM

Thanks for that, but Im not sure anything in there answered my question. What I'm looking for is how to determine the date with another date For example, I have a date 6/01/2004 and I want to know the date of the prior Sunday which would be 5/30/2004. Another example would be 6/10/2004, the Sunday date would be 6/6/2004.

I would like something like

Code:

 date --date="6/7/2004"  "1 day ago"

and have it display 6/6/2004

Thanks.

chrisk5527 · 06-10-2004, 02:57 PM

I think I figured a solution out, but now I need to figure out how many days ago a date was. For example, 6/6/2004 was 4 days ago.