Shell script to copy file name with part of directory
 

Here's the situation. I need to figure out who to take a file from a directory and automatically copy it as follows..

For example if i had a file in this directory

/usr/local/backups/db/01.18.05.Tuesday.gz

the desired result would be to copy this file into a new directory such as /copy with the name db.01.18.05.Tuesday.gz. So in addition to copying i need to strip off the directory name it's in and append it to the beginning of the file.

:confused:

Any help is greatly appreciated.

It ain't pretty, but:
That turns the full path of the filename into the filename you wanted. Just run it and you'll see :)

There might be a much more elegant solution using basename and dirname, but I like sed, and the command above works (if a bit cryptic).

EDIT:
Actually, that command will break if the file is stored in the root (/) directory, or a relative directory with only one slash in the path. Just fyi.

cp "$FILE" /copy/db.`basename "$FILE"`

should do the trick. e.g.:
cp /home/dave/hello.txt /copy/db.`basename /home/dave/hello.txt`

Dave

That doesnt append the directory name to the file though. I end up with a file called db.hello.txt instead of the desired dave.hello.txt.

Got it.

cp /home/dave/hello.txt /copy/`basename /home/dave/`.hello.txt

Thanks ilikejam & DarkHelmet. :)

That should do it.