Script Refuses to Work.

Zaiachkowski · 06-13-2006, 01:12 PM

Script I Wrote refuses to work and I dont know why?

#!/bin/sh tar -Pvcf ../`uname -r`/`date "+%m%d%y.tar."` --exclude /tmp --exclude /var/run --exclude /dev --exclude /backup $* /

unSpawn · 06-13-2006, 02:16 PM

Please post *exact* errors instead. It's much more efficient.
If you have script problems the first thing is to run it in debug mode.
With values expanded there's more chance you see where the error is at.

MensaWater · 06-13-2006, 02:33 PM

Your interpreter line and your command line should be separate:

Code:

#!/bin/sh 

tar -Pvcf ../`uname -r`/`date "+%m%d%y.tar."` --exclude /tmp --exclude /var/run --exclude /dev --exclude /backup $* /

As unspawn indicated you should give your errors when asking questions as it helps to debug. I'm sure the above is an issue but may not be your only one.

The "#!...." is special syntax as first line of a shell script that tells it what interpreter (shell, perl, other...) to use to execute what follows that line.

homey · 06-13-2006, 02:58 PM

I would work with the filename and just echo it to get that working, then put it in the tar script. I don't think using a / in the filename is a good idea and underscore may be a better choice.

Code:

#!/bin/sh

filename=$(uname -r)'/'$(date '+%m%d%y').tar.gz
echo $filename

Code:

#!/bin/sh

filename=$(uname -r)'/'$(date '+%m%d%y').tar.gz
tar -Pvcf $filename --exclude /tmp --exclude /var/run \
--exclude /dev --exclude /backup $* /