Script help for awk and timing commands

jakev383 · 12-13-2006, 08:44 PM

I am trying to do a DNS query and find out how long the query took. I'm currently using:

[root@as1 ~]# time dig yahoo.com

Which gives the following results:

; <<>> DiG 9.3.1 <<>> yahoo.com
;; global options: printcmd
;; Got answer:
;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 17255
;; flags: qr rd ra; QUERY: 1, ANSWER: 2, AUTHORITY: 0, ADDITIONAL: 0

;; QUESTION SECTION:
;yahoo.com. IN A

;; ANSWER SECTION:
yahoo.com. 258 IN A 216.109.112.135
yahoo.com. 258 IN A 66.94.234.13

;; Query time: 2 msec
;; SERVER: 216.55.144.5#53(216.55.144.5)
;; WHEN: Wed Dec 13 21:35:33 2006
;; MSG SIZE rcvd: 59

real 0m0.011s
user 0m0.008s
sys 0m0.004s

But the ONLY part I care about is the real time (0m0.011s). Even then, I'm really only concerned with the integer (0.011), since I'll be using this to compare against another number. You can probably see where I'm going with this. Anyway, I CAN write the data to a test file and grep it out, but am a little fuddled on how to go about it. Does anyone have any suggestions, or a better idea for this? I'm sure awk is what I want for this, but I'm not that awk-savvy.
Any help is greatly appreciated!

matthewg42 · 12-13-2006, 10:20 PM

See the TIMEFORMAT variable in the bash manual page to see how to customize the time output. e.g.

Code:

$ TIMEFORMAT="J. R. Bob Dobbs has made %R million dollars today"
$ time sleep 1
J. R. Bob Dobbs has made 1.007 million dollars today

jakev383 · 12-18-2006, 07:35 PM

Quote:

Originally Posted by matthewg42

See the TIMEFORMAT variable in the bash manual page to see how to customize the time output. e.g.

Code:

$ TIMEFORMAT="J. R. Bob Dobbs has made %R million dollars today"
$ time sleep 1
J. R. Bob Dobbs has made 1.007 million dollars today

Thanks, that gave me the push in the right direction. I now set the TIMEFORMAT variable in the top of my script, and call dig with the +short option to just give me 2 lines of text to deal with.