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Something like this in the script called by cron, located in the 'cron.foldername' folder (I'm not great with scripting either, but I think this would work):
Code:
#!/bin/sh
weekday=`date +%A`
if [ $weekday == "Monday" ]; then
< insert job here >
fi
and the cron would be run as you figured: for the first 7 days each month, by adding this to the root crontab (or whoever's crontab it is) like:
Hey that looks great and much more complicated looking than I would have come up with! So many options to the 'date' command does it work how you want?
yeah I thought about that one but it doesn't work, here's the relevent part of the man page:
Quote:
Note: The day of a command’s execution can be specified by two fields —
day of month, and day of week. If both fields are restricted (i.e.,
aren’t *), the command will be run when either field matches the cur‐
rent time. For example,
‘‘30 4 1,15 * 5’’ would cause a command to be run at 4:30 am on the 1st
and 15th of each month, plus every Friday.
Indeed, here is another method I found. The following will run only on Mondays instead of everyday but the test is only true if it is the first week. Also easily modified for any day of any week.
0 7 * * 1 [ `date +\%e` -gt 0 -a `date +\%e` -lt 8 ] && some command
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