Hello All!

I have a big directory with lots of files on it. I'd like to know how Can I remove
files through it date.

For example:

-rw------- 1 test rodrigo 1060864 Jul 27 14:11 mm.20881.mem
-rw------- 1 test rodrigo 0 Jul 27 14:11 mm.20881.sem
-rw------- 1 test rodrigo 1060864 Jul 28 17:28 mm.2092.mem
-rw------- 1 test rodrigo 0 Jul 28 17:28 mm.2092.sem
-rw------- 1 test rodrigo 1060864 Jul 28 17:28 mm.2095.mem
-rw------- 1 test rodrigo 0 Aug 28 17:28 mm.2095.sem
-rw------- 1 test rodrigo 1060864 Aug 27 14:13 mm.20973.mem

Imagine there are 3 hundreds of files like those above, it were created on July and
August, How can I delete only the July files??

Thank You!

Hi,

There is more then one way of doing this, this came to mind first:

ls -l | awk '/ Jul / { print $9 }'

The above will give you all the files in July, to remove them add the following:

ls -l | awk '/ Jul / { print $9 }' | xargs rm

The above will fail if: filename(s) have special characters in them (spaces, to name just one).

Hope this helps.

Fantastic!!!

Hi druuna,

I've been reading a shell script book "Programação Shell Linux",
it is one of the best here in Brazil, there is a chapter about AWK,
I've read it about twice but I don't know Why I'm getting some difficulties
to understand it. Now I'm seeing this command is very important, I'll read it again.

Thank You very much!

Hi,

If you like books (I do) then this one is 'a must':

O'reilly's Sed & Awk.

Both sed and awk are explained, from the basics to more advanced topics.

I'll you take a look at it. It seems to be good, it's not easy to find out
books talking about specific topics like this one, thank's for your
suggestion.