One line command - bash
 

Not sure if this is the right section for this question


I need a one-liner for this task: print the scripts that are being run at the begining of the current runlevel.

so fare I have
runlevel | cut -f 2 -d " "

Next, I need a ls, but I don't know how to set the path parameter to
/etc/rcx.d/ where x is the number that is displayed when using the runlevel | cut command.
Please help.

Try something likeUse $rlvl where needed.

You can take the result of a command and use it in another using either `backticks` or $(like this). I favour the $() syntax because it less likely to lead to a mistake (i.e. using the wrong type of quote), and is nestable.

The programs which will be run for a given runlevel are the ones with S at the start of the file name, so if you want to list the files which are executed, you can do it like this:

thanks. It works just fine