[SOLVED] oldest files will delete after reach to 21G

ghaedi591 · 11-07-2011, 04:31 AM

I want to delete the oldest files in a folder after reaching to 21Gig.
for this action i write the following code.
Dose it ok?
...
DUMP_DIR_SIZE_BEFOR=$(du -sm $ODP_PATH | awk '{print $1}')
while [DUMP_DIR_SIZE_BEFOR gt 21000]
do
rm "ls $ODP_PATH -lrt|tail -1"
DUMP_DIR_SIZE_BEFOR=$(du -sm $ODP_PATH | awk '{print $1}')
done

Narges.

Cedrik · 11-07-2011, 05:11 AM

Maybe test :

Code:

find $ODP_PATH -size +21G | xargs rm

(do without "| xargs rm" before to be safe)

ghaedi591 · 11-07-2011, 05:52 AM

it seems that your code delete only the file which has 21G size but it is not my porpuse.
i want to delelte file from oldest to reach to less than 21G .
All of files in this directory are less than 1G.

Cedrik · 11-07-2011, 06:24 AM

Ok, I get it

Use head rather than tail because tail will output newest files (last line of ls -lrt output)

Code:

DUMP_DIR_SIZE_BEFOR=$(du -sm $ODP_PATH | awk '{print $1}')

while [ "$DUMP_DIR_SIZE_BEFOR" -gt 21000 ]
do
    rm $(ls -rt $ODP_PATH | head -n1)
    DUMP_DIR_SIZE_BEFOR=$(du -sm $ODP_PATH | awk '{print $1}')
done

ghaedi591 · 11-07-2011, 09:11 AM

Thanx.Ur Reply was helpfull.
but it seems ".. du -sm... " is not working in my code!
what is wrong?

Cedrik · 11-07-2011, 10:20 AM

I don't know... $ODP_PATH is set before in the script ?
Maybe check how $ODP_PATH is initialized