LinuxQuestions.org - mandatory and optional arguments

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mandatory and optional arguments

Hi ,
I am using getopts to take parse optional arguments but i also pass in mandatory arguments first

Code:

#!/bin/bash





print_usage()

{

    perror "$@"

}

arg1="$1"

arg2="$2"

shift 2

while getopts f:d: opt

do

  case $opt in

              f) file="${OPTARG}";;

              d) dir="${OPTARG}";;

              ?) print_usage $0

            exit 1;;

  esac

done

echo "Argument 1 = $arg1"

echo "Argument 2 = $arg2"

echo "File=$file"

echo "Dir=$dir"

./script arg1 arg2 -f file -d dir this works fine

But when i pass in the wrong number of mandatory arguments and pass in the optional argument the command line gets all messed up like so

./script arg1 -f BLAH -d DIR
Argument 1 = arg1
Argument 2 = -f
File=
Dir=

Any ideas how to stop this ???

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