ls

baddah · 07-24-2008, 03:52 AM

Hi,

I'm doing the following command which gives me all the matching entries,but i'd like to see only the filename,not the full path,so i'm doing this..

Code:

[root@accountingdb scripts]# ls --format single-column /var/www/html/CSA20June/B_Berg/*20080620*
/var/www/html/CSA20June/B_Berg/ipB_Berg200806200001.cgi

but i only want the filename(ipB_Berg200806200001.cgi) returned.

IS there some way in ls to throw away the full path, and only list the filename? I went through the man pages, but i could not find anything. I've tried some pipe commands to grep as well, but my grep skills is not nearly good enough it seems.

Any suggestions how can i achieve this?

Thanks

dipuasks · 07-24-2008, 04:09 AM

First redirect the whole output to a file say result.txt

Then count the number of / comes in the file path(I hope all the files are from same folder as per your above query) and run this command:

cut -d / -f# /path/to/result.txt

Where # is the number of slashes+1 i.e, for the path /var/www/html/CSA20June/B_Berg/ipB_Berg200806200001.cgi, the # should be 7.

I am not a scripting master, I had got this solution for a similar problem earlier and it works!

--Dipu
----------------------------
Windows? reboot. Linux? Be root!!

http://www.smartdipu.info

arungoodboy · 07-24-2008, 04:10 AM

You can prefix it with the basename command.

Code:

basename `ls /some/long/path/*extension`

will give you only the filename.

edit: apparently basename takes only one arg. To workaround that, xargs seems to do fine:

Code:

ls /some/path/*txt | xargs -n1 basename

baddah · 07-24-2008, 04:36 AM

Quote:

Originally Posted by arungoodboy

edit: apparently basename takes only one arg. To workaround that, xargs seems to do fine:

Code:

ls /some/path/*txt | xargs -n1 basename

This works perfectly thanks. I find it a bit strange that one can't do this directly from ls,but i guess as long as there is a way do do it, all is well.

Thanks

arungoodboy · 07-24-2008, 04:58 AM

If you actually cd to the folder first and then do ls, you'll get the filename like you want it. But when you pass the path to ls, it displays that path followed by the filename.

toto10 · 03-06-2010, 05:29 PM

ls -m1

trey85stang · 03-06-2010, 05:47 PM

looks like ls -m1 is the weiner...

but if you need a loop to process the files.. id go like this

Code:

for f in /var/www/html/CSA20June/B_Berg/*20080620*
do
  echo ${f##/*/}
done

you could also test if $f is a direcotyr or not if you have directories you dont want to see....