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Old 07-24-2008, 04:52 AM   #1
baddah
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ls - Do not list full path only filename


Hi,

I'm doing the following command which gives me all the matching entries,but i'd like to see only the filename,not the full path,so i'm doing this..

Code:
[root@accountingdb scripts]# ls --format single-column /var/www/html/CSA20June/B_Berg/*20080620*
/var/www/html/CSA20June/B_Berg/ipB_Berg200806200001.cgi
but i only want the filename(ipB_Berg200806200001.cgi) returned.

IS there some way in ls to throw away the full path, and only list the filename? I went through the man pages, but i could not find anything. I've tried some pipe commands to grep as well, but my grep skills is not nearly good enough it seems.

Any suggestions how can i achieve this?

Thanks
 
Old 07-24-2008, 05:09 AM   #2
dipuasks
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First redirect the whole output to a file say result.txt

Then count the number of / comes in the file path(I hope all the files are from same folder as per your above query) and run this command:

cut -d / -f# /path/to/result.txt

Where # is the number of slashes+1 i.e, for the path /var/www/html/CSA20June/B_Berg/ipB_Berg200806200001.cgi, the # should be 7.

I am not a scripting master, I had got this solution for a similar problem earlier and it works!


--Dipu
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Windows? reboot. Linux? Be root!!

http://www.smartdipu.info
 
Old 07-24-2008, 05:10 AM   #3
indeliblestamp
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You can prefix it with the basename command.
Code:
basename `ls /some/long/path/*extension`
will give you only the filename.

edit: apparently basename takes only one arg. To workaround that, xargs seems to do fine:
Code:
ls /some/path/*txt | xargs -n1 basename

Last edited by indeliblestamp; 07-24-2008 at 05:17 AM. Reason: added better version
 
Old 07-24-2008, 05:36 AM   #4
baddah
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Quote:
Originally Posted by arungoodboy View Post
edit: apparently basename takes only one arg. To workaround that, xargs seems to do fine:
Code:
ls /some/path/*txt | xargs -n1 basename
This works perfectly thanks. I find it a bit strange that one can't do this directly from ls,but i guess as long as there is a way do do it, all is well.

Thanks
 
Old 07-24-2008, 05:58 AM   #5
indeliblestamp
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If you actually cd to the folder first and then do ls, you'll get the filename like you want it. But when you pass the path to ls, it displays that path followed by the filename.
 
Old 03-06-2010, 06:29 PM   #6
toto10
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Another way to list files using ls using only ls

ls -m1
 
Old 03-06-2010, 06:47 PM   #7
trey85stang
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looks like ls -m1 is the weiner...

but if you need a loop to process the files.. id go like this

Code:
for f in /var/www/html/CSA20June/B_Berg/*20080620*
do
  echo ${f##/*/}
done
you could also test if $f is a direcotyr or not if you have directories you dont want to see....
 
Old 06-14-2013, 03:08 PM   #8
Bryan H
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Not quite

In ls -m1 the -m is overkill

ls -1 is what you're actually doing (-1 overrides the other parameter)
 
Old 06-14-2013, 05:00 PM   #9
suicidaleggroll
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Quote:
Originally Posted by Bryan H View Post
In ls -m1 the -m is overkill

ls -1 is what you're actually doing (-1 overrides the other parameter)
Neither of those work on my machine...

Code:
$ ls /home/user/comps/srv1/chassis/*
/home/user/comps/srv1/chassis/SC846.pdf
$ ls -1 /home/user/comps/srv1/chassis/*
/home/user/comps/srv1/chassis/SC846.pdf
$ ls -m1 /home/user/comps/srv1/chassis/*
/home/user/comps/srv1/chassis/SC846.pdf
$ ls /home/user/comps/srv1/chassis/* | xargs -n1 basename
SC846.pdf
The man page for -1 says "list one file per line" and for -m says "fill width with a comma separated list of entries", neither of which claim to do what the OP is asking, and neither of which actually do what the OP is asking either (at least not on my machine).

Last edited by suicidaleggroll; 06-14-2013 at 05:02 PM.
 
Old 06-14-2013, 05:05 PM   #10
linuxCode
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Quote:
Originally Posted by arungoodboy View Post
If you actually cd to the folder first and then do ls, you'll get the filename like you want it. But when you pass the path to ls, it displays that path followed by the filename.
The find command can list filenames recursively and omit the full paths by using printf

Example
Code:
find /path/to/directory/ -type f <options> -printf "%f\n"
This will go through the directory you listed including subs and show only the filenames without the full paths.

Last edited by linuxCode; 06-14-2013 at 05:40 PM.
 
Old 06-14-2013, 06:53 PM   #11
unSpawn
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http://mywiki.wooledge.org/ParsingLs as in indeed one shouldn't use 'ls' but find.
 
Old 06-16-2013, 05:51 AM   #12
salasi
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Well, yes, you shouldn't really parse the output of 'ls', because it can, potentially, be quite variable over releases and with different set-ups, but just this once...

i) Does 'ls -D -1' do what you are asking for? I can't say that I know all that much about 'dired' mode, but superficially the output looks quite similar to what you are asking for, once it has been put into single column mode. Obviously, all the warnings of imminent doom, bad karma and possibly even garden gnomes and stone cladding, from the wooledge link apply.
ii) If you were going to parse the 'path...filename' output to just give 'filename', you would want to use 'basename' to strip, errr, the basename from the full path string (while busily noting, but ignoring for this application, its partner 'dirname'). I don't see any case whatever for doing this, but you should probably note the existence of basename/dirname in case that you have need of them, in future.
 
Old 06-17-2013, 01:21 AM   #13
chrism01
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I agree with suicidaleggroll, none of the ls switches work for what the OP asked, (inc -D -1).
Use xargs, or param expansion (post #7) or (better) find.
 
  


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