I have a shell scripting question

bartock · 03-06-2008, 12:54 PM

Hi;

When I run this snippet of script:

echo "/sbin/ifconfig | grep 'inet addr' | awk '{print $1, $2, $3}'" >> $STATSCRIPT

To $STATSCRIPT it writes :

/sbin/ifconfig | grep 'inet addr' | awk '{print , , }'

I know there is some escape sequences or something, but how can I get the $1,$2, etc to echo into my script. What am I forgetting??

G

kaz2100 · 03-06-2008, 01:06 PM

Hya,

Code:

echo `ls`

see what happens if you do above.

Happy Penguins!

kilgoretrout · 03-06-2008, 01:15 PM

I don't understand why you are using echo. Have you tried:

/sbin/ifconfig | grep 'inet addr' | awk '{print $1, $2, $3}' >> $STATSCRIPT

That should print $1, $2, and $3 and direct the output to $STATSCRIPT.

bartock · 03-06-2008, 01:41 PM

I guess I should be clearer - This line is part of a script that is going to be automatically run on multiple machines that are being deployed to the field - so, this is part of a script that is being put on the machine to be run.

Follow??

Uncle_Theodore · 03-06-2008, 02:37 PM

Quote:

Originally Posted by bartock

I guess I should be clearer - This line is part of a script that is going to be automatically run on multiple machines that are being deployed to the field - so, this is part of a script that is being put on the machine to be run.

Follow??

It's still not clear, why you're using echo...
What exactly do you want to be written in your $STATSCRIPT file?
In other words, what is the desired output of this line in your script?

forrestt · 03-06-2008, 02:46 PM

OK, I'm not sure that was clearer, but somehow I think I know what you are asking. You don't want the $1, $2, and $3 values appended to $STATSCRIPT, you want to add a command to the end of $STATSCRIPT that when executed will output "$1 $2 $3".

I attempted a whole bunch of ways to escape things, but this is the only thing I could come up with:

Code:

echo "/sbin/ifconfig | grep 'inet addr' | awk '"'{print $1, $2, $3}'"'" >> $STATSCRIPT

HTH

Forrest