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How to change function parameter value and return back to the main shell program

Hi All,
In shell programming, I am trying to call a function and pass parametrs to it, I want to change the values of the parameters and return them back to the main shell script, so anyone could help me in this matter???

example:

Code:

#!/bin/bash

function names ()

{

        echo -e "Inside the function $1"

        echo -e "Inside the function $2"



        #here I am changing the values of the parameters.

        $1=Sahab

        $2=Alaa



        return

}



name1=Bassam

name2=Farah



echo -e "$name1\n"

echo -e "$name2\n"



names $name1 $name2



echo -e "$name1\n"

echo -e "$name2\n"

that was the first part of my question. Now the second part is that is it possible to return a value with the return keyword from inside the function to the main program?

example

Code:

#!/bin/bash

function addition ()

{

        return `expr $1 + $2`

}



echo < addition 5 10

Please correct if I am mistaken

Regards
Bassam

You have to use variables that retain scope in and out of the function

Code:

#!/bin/bash

name1=""

name2=""

function names ()

{

        echo -e "Inside the function $1"

        echo -e "Inside the function $2"



        #here I am changing the values of the parameters.

        # $1 and $2 -- these are local ONLY to the function



        name1=$1 

        name2=$2 

        

        return

}



name1=Bassam

name2=Farah



echo -e "$name1\n"

echo -e "$name2\n"



names "XXX" "ZZZZ"



echo -e "$name1\n"

echo -e "$name2\n"