Grep with Echo

Myiagros · 04-26-2010, 09:53 AM

I'm wondering if there is a way to use grep with echo to get part of a path name?

I have my directory set as a variable - PROJECT=/opt/jobs/test

I want to be able to echo this and use grep to remove /opt/jobs/

echo $PROJECT | grep .....

Output should be: test

centosboy · 04-26-2010, 09:57 AM

Quote:

Originally Posted by Myiagros

I'm wondering if there is a way to use grep with echo to get part of a path name?

I have my directory set as a variable - PROJECT=/opt/jobs/test

I want to be able to echo this and use grep to remove /opt/jobs/

echo $PROJECT | grep .....

Output should be: test

awk will do this

Code:

echo $PROJECT | awk -F '/' '{print $4}'

Myiagros · 04-26-2010, 10:03 AM

Perfect! Thanks!

colucix · 04-26-2010, 10:12 AM

Even more simple using substring removal in parameter substitution:

Code:

echo ${PROJECT##*/}

this mimics the basename command.