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Just out of curiosity, I wonder if the echo statement is a command or a shell built-in. Indeed, it is a shell built-in... but it has also its own executable. The type built-in confirms:
Code:
# type -a echo
echo is a shell builtin
echo is /bin/echo
and the Advanced Bash Scripting Guide, too
Quote:
This command is a shell builtin, and not the same as /bin/echo, although its behavior is similar.
Here are my questions: if the behavior is similar in what they differ? And when I put an echo statement (without path) in a BASH script which one is executed, the built-in or the command?
Or in other words: who wrote the source of the command /bin/echo and why?
I am guessing the reason is evolution as shells like the original sh did not have echo built in; hence, it was developed as a standalone tool., then, of course bash can along and rendered the command line echo redundant.
The /bin/echo utility is developed by GNU according /bin/echo --help
Thanks Harry, your guess sounds reasonable. I found a little history of the echo command through the various UNIX shells, here. It looks like the original Bourne shell written for Unix Version 7 didn't have echo as a built-in. Steve Bourne himself in the official documentation on 1978 states:
Quote:
echo is a standard UNIX command that prints its arguments, separated by blanks
Also, now I see that the shell uses its own built-in, since obviously it takes precedence over an external command. You gave me the correct suggestion to demonstrate: if I type
Code:
echo --help
it simply echoes the string "--help", whereas the external command /bin/echo prints out the usage.
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