dirname basename; how to capture extensions from bash?

carl0ski · 07-21-2005, 09:27 PM

anyone know how to capture a file extension in bash?

basename /home/file.txt
file.txt

dirname /home/file.txt
/home/file

crabboy · 07-21-2005, 10:33 PM

how about:

Code:

basename /usr/src/file.txt | cut -s -d'.' -f2

It will not work correclty if there are more than one '.' in the filename.

So perhaps a regular expression:

Code:

for i in `ls`; do
echo $i{##*[.]} 
done

carl0ski · 07-22-2005, 07:26 AM

Quote:

Originally posted by crabboy
how about:

Code:

basename /usr/src/file.txt | cut -s -d'.' -f2

It will not work correclty if there are more than one '.' in the filename.

So perhaps a regular expression:

Code:

for i in `ls`; do echo $i{##*[.]} done

brilliant thank you

cp "$(dcop amarok player path)" "$(dirname "$(dcop amarok player path)")"/0"$(dcop amarok player track)"\ -\ "$(dcop amarok player artist)"\ -\ "$(dcop amarok player title)"."$(basename "$(dcop amarok player path)" | cut -s -d'.' -f2)"

## */ Copies song currently playing in Amarok to the same directory it already is with filename based on id3track - id3artist - id3title . original extension /*
Basically mv will rename it instead. cp is for debugging purposes

i don't know how your second suggestion can be used however the first one is more than sufficient.

and what does the
"| "
do in the command basename /usr/src/file.txt | cut -s -d'.' -f2