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oliveoyl

02-14-2019 09:48 AM

Bracket wildcard usage command line

Hi,

I'm trying to use bracket wildcard on the command line like this:

grep SOMETHING /var/log/node/2019/02/[01-07]/messages

Here is the layout to give you an idea:

## pwd
/var/log/node/2019/01

## ls
01 03 05 07 09 11 13 15 17 19 21 23 25 27 29 31
02 04 06 08 10 12 14 16 18 20 22 24 26 28 30

What is the correct syntax to use bracket wildcard like I want to above?

Thank you.

l0f4r0

02-14-2019 09:53 AM

Code:

grep "SOMETHING" /var/log/node/2019/02/{01..07}/messages

oliveoyl

02-14-2019 01:15 PM

That worked great from the command line!

Now I tried to put it in a script with 01 and 07 as variables but it won't read it:

## DAY1=01; DAY7=07
## echo $DAY1
01
## echo $DAY7
07
## grep "SOMETHING" /var/log/node/2019/02/{$DAY1..$DAY7}/messages
grep: /var/log/node/2019/02/{01..07}/messages: No such file or directory

teckk

02-14-2019 01:50 PM

Code:

echo {01..07}

01 02 03 04 05 06 07

Code:

a=01

b=07

echo {"$a".."$b"}

{01..07}

Code:

c=({01..07})

for i in "${c[@]}"; do echo "$i"; done

01

02

03

04

05

06

07

Code:

c=({01..07})

for i in "${c[@]}"; do

    echo "grep "SOMETHING" /var/log/node/2019/02/"$i"/messages"

done

grep SOMETHING /var/log/node/2019/02/01/messages

grep SOMETHING /var/log/node/2019/02/02/messages

grep SOMETHING /var/log/node/2019/02/03/messages

grep SOMETHING /var/log/node/2019/02/04/messages

grep SOMETHING /var/log/node/2019/02/05/messages

grep SOMETHING /var/log/node/2019/02/06/messages

grep SOMETHING /var/log/node/2019/02/07/messages

Code:

for i in /var/log/node/2019/01/{01..30}/messages; do

    echo "grep 'SOMETHING' "$i""

done

rknichols

02-14-2019 02:05 PM

Quote:

Originally Posted by oliveoyl (Post 5962070)

## DAY1=01; DAY7=07
## echo $DAY1
01
## echo $DAY7
07
## grep "SOMETHING" /var/log/node/2019/02/{$DAY1..$DAY7}/messages
grep: /var/log/node/2019/02/{01..07}/messages: No such file or directory

The problem is with the order in which bash does expansions. Brace expansion is performed before parameter expansion, and those literal characters "$DAY1..$DAY7" are not a legitimate brace expression. There is no simple way to do what you want in bash. You need to do one of:

write a loop to generate the set of strings,
use an external command like seq with its --format option, or
perhaps use zsh, where "{$Var1..$Var2}" does what you want here.

MadeInGermany

02-14-2019 03:47 PM

Better check for existence in the loop and skip non-existent files

Code:

for f in /var/log/node/2019/01/{01..30}/messages; do

    [ -f "$f" ] || continue

    echo grep 'SOMETHING' "$f"

done

l0f4r0

02-15-2019 06:50 AM

Since OP has requested a solution with variables, I suggest the following:

Code:

#!/bin/bash

startVar=01

endVar=07

for ((i=startVar;i<=endVar;i++))

do

        if ((i<10))

        then 

                [[ -f /var/log/node/2019/02/0$i/messages ]] && grep "SOMETHING" "/var/log/node/2019/02/0$i/messages"

        else 

                [[ -f /var/log/node/2019/02/$i/messages ]] && grep "SOMETHING" "/var/log/node/2019/02/$i/messages"

        fi

done

MadeInGermany

02-15-2019 01:00 PM

But that looks a bit, well, sub-optimal, doesn't it?

Regarding post#1
The "bracket wildcard" is a "character set". Represents one character. So 0[0-7] or 1[0-7] works. But if the range spans over a decade then this method fails.

BTW the character set is really a "wildcard" like * because it is matched against files, and generates what it finds.
In contrast, { } generates a range unconditionally, without matching files.

l0f4r0

02-16-2019 04:30 AM

^ I agree with everything you said.
Actually, I suggested #7 because that's the only solution that came to my mind to satisfy the initial OP's request, namely to define range with variables inside a script...

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