bash scripting - referring to external arguments into loops
Here is a simplified version of my problem:
I have a script and would like it to handle several arguments: a1,a2,a3,a4..................
I usually indicate them with $1, $2, $3.......
i want it to print on screen a2,a3.........
for (( i = 2 ; i < $# ; i++ ))
echo :scratch: ????????????????
if I write $i it does not work because it prints "i" values and not a1,a2..........
i tried various things but none worked
$[$i] ; $("$"$i"") ; $ $i ; $"$i"
I think there must be an easy answer to write external arguments in a loop but I couldn't find it.
Can anyone help?
Thanks a lot
PS Does anyone know the bash scripting command which plays the role of the BREAK command in c++ ??
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Closed - as per above.
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