I have a question like this:

When I use "ls *.jpg", it's gonna print out every files jpg in my folder. the question is : How can I actually use each file as a variable ?

For example,

$ ls *jpg > new
$ cat new
face.jpg
owl-face.jpg
man-face.jpg
$

So I have 3 jpg files in "new".

I want to make :
face1 = "face.jpg"
face2 = "owl-face.jpg"
face3 = "man-face.jpg"
to use:
echo $face1, $face2, $face3


Thanks a lot

I'm not sure I understand exactly what you're asking, but if you want to run a command for every item in a glob, you can use the following format (a trick I probably use 10 times a day)

You can put any number of commands between "do" and "done". Just terminate each with a semicolon.

It's also often useful to use a command substition in the above format.

Or, if your files are scattered about, you can have the find command run commands on files.

Note that \{\} gets replaced with the filename, and the \; is manditory
(This particular example would do the exact same thing that that find normally does, though)

exactly what I need, thank you