Hi

Can any one help me for the following query.

I have one file which has the entries like as follows

Mar 23 09 abcd
Mar 24 09 abcd
Mar 24 11 pqrs
Mar 25 13 wxyz
Mar 25 13 wxyz
Mar 26 22 abcd
Mar 26 01 abcd
Mar 26 02 abcd
Mar 27 03 wxyz
Mar 27 06 wxyz
Mar 28 06 wxyz
Mar 29 07 pqrs
Mar 29 07 pqrs

I just want to find out the values which is greater than "Mar 25"

On the basis of second column value I want to print?

output should be all the entries greater than or equal to "25"

How can we use operators here in this example?

Please help me on this query

I do not do programing any more this days ,but as I remember the Bolean expression where :
IF
And
Or
>
<

equals 0r >
Eguals Or <

The last 2 expression I can not find them on my keyboard using this expression it must be not to difficult to do what you like to do But I do not know if you can use them in the programming language you use
Hopefully this use full for you

all the best

Do you want to test:
Numbers greater than 25?
OR
Dates greater than March 25?

(There is a big difference in the code...)

The best way to deal with this kind of thing is to download a copy of the Advanced Bash Scripting Guide and use it for searching. Here is a link to the relevant section:

http://tldp.org/LDP/abs/html/comparison-ops.html
(This is for the simple number test)

awk '{ if ($1==MAR && $2 > 25) print $0 }'

hope this helped.

Fedora Development