problem with maths

redduck666 · 02-12-2005, 11:48 AM

i've got a problem with maths, can anyone please help me solve it.

2x^2
---------=?
x^4+1

in case i expressed myself bad the above is the same as (2x^2)/(x^4+1)

i would like to know how much ? is, i would also like to know how you come to that result.

thanks

XavierP · 02-12-2005, 11:51 AM

Which bit of homework is this?

Quote:

From the Rules
Do not expect LQ members to do your homework - you will learn much more by doing it yourself.

redduck666 · 02-12-2005, 12:01 PM

the problem is that we were taught that in school 2 years ago, now we need it, the trouble is that teacher refuses to explain it to us one more time.

this monday we are writing a test paper, so any help appriciated

Boffy · 02-12-2005, 12:45 PM

Are you sure there thre is no =0 in the equation. Without it i dont think you can solve it, only simplify. What year are you in this work may be above me.

redduck666 · 02-12-2005, 01:14 PM

ok forget my first question. i'm trying to draw this f(x)=(x^2 -2x +1)/(8-2x)

http://tinypic.com/1pt9vl

^^this is how it looks like, according to our book. it is more or less clear to me why everything is in the way it is. the only thing i have no idea how to do is the red line on the above pic. anyone cares to explain me why the red line is y=-x/2 -1.

rksprst · 02-12-2005, 01:17 PM

(2x^2)/(x^4 + 1) = ((2x^2) * (1/ (2x^2)) ) / ((x^4 + 1) * (1 / (2x^2))) = 1 / ( (x^2)/2 + 1/(2x^2))

and i ALWAYS mess up here, just to make sure if 1 / (b / c) then you get c / b right? if thats right then the next part is right too

= (2 / x^2) + 2x^2

thats as far as i can simplify it

edit: so typing it up neatly:

Code:

                1
              ------
2x^2          2x^2                     1                         2
---------- *------------ =  ------------------------ =  -----------------  + 2x^2
x^4 + 1         1                x^2              1             x^2
              ------           -------    +    -------
              2x^2               2              2x^2

rksprst · 02-12-2005, 01:50 PM

About your second problem I don't remember, but i think it involves taking the limit (or is that for horizontal asymptotes?)

redduck666 · 02-12-2005, 02:33 PM

http://mathforum.org/library/drmath/view/53777.html

some dude named chest on ##linux gave me this link. it solved my problem thanks for help people.