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 02-12-2005, 11:48 AM #1 redduck666 Member   Registered: Dec 2004 Posts: 32 Rep: problem with maths i've got a problem with maths, can anyone please help me solve it. 2x^2 ---------=? x^4+1 in case i expressed myself bad the above is the same as (2x^2)/(x^4+1) i would like to know how much ? is, i would also like to know how you come to that result. thanks Last edited by redduck666; 02-12-2005 at 11:51 AM.
02-12-2005, 11:51 AM   #2
XavierP
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Rep:
Which bit of homework is this?
Quote:
 From the Rules Do not expect LQ members to do your homework - you will learn much more by doing it yourself.

Last edited by XavierP; 02-12-2005 at 11:53 AM.

 02-12-2005, 12:01 PM #3 redduck666 Member   Registered: Dec 2004 Posts: 32 Original Poster Rep: the problem is that we were taught that in school 2 years ago, now we need it, the trouble is that teacher refuses to explain it to us one more time. this monday we are writing a test paper, so any help appriciated
 02-12-2005, 12:45 PM #4 Boffy Member   Registered: Jul 2003 Location: Durham, UK Distribution: Ubuntu 8.04 Posts: 419 Rep: Are you sure there thre is no =0 in the equation. Without it i dont think you can solve it, only simplify. What year are you in this work may be above me.
 02-12-2005, 01:14 PM #5 redduck666 Member   Registered: Dec 2004 Posts: 32 Original Poster Rep: ok forget my first question. i'm trying to draw this f(x)=(x^2 -2x +1)/(8-2x) http://tinypic.com/1pt9vl ^^this is how it looks like, according to our book. it is more or less clear to me why everything is in the way it is. the only thing i have no idea how to do is the red line on the above pic. anyone cares to explain me why the red line is y=-x/2 -1.
 02-12-2005, 01:17 PM #6 rksprst Member   Registered: Jan 2004 Distribution: OS X 10.4 Posts: 172 Blog Entries: 1 Rep: (2x^2)/(x^4 + 1) = ((2x^2) * (1/ (2x^2)) ) / ((x^4 + 1) * (1 / (2x^2))) = 1 / ( (x^2)/2 + 1/(2x^2)) and i ALWAYS mess up here, just to make sure if 1 / (b / c) then you get c / b right? if thats right then the next part is right too = (2 / x^2) + 2x^2 thats as far as i can simplify it edit: so typing it up neatly: Code: ``` 1 ------ 2x^2 2x^2 1 2 ---------- *------------ = ------------------------ = ----------------- + 2x^2 x^4 + 1 1 x^2 1 x^2 ------ ------- + ------- 2x^2 2 2x^2``` Last edited by rksprst; 02-12-2005 at 01:51 PM.
 02-12-2005, 01:50 PM #7 rksprst Member   Registered: Jan 2004 Distribution: OS X 10.4 Posts: 172 Blog Entries: 1 Rep: About your second problem I don't remember, but i think it involves taking the limit (or is that for horizontal asymptotes?)
 02-12-2005, 02:33 PM #8 redduck666 Member   Registered: Dec 2004 Posts: 32 Original Poster Rep: http://mathforum.org/library/drmath/view/53777.html some dude named chest on ##linux gave me this link. it solved my problem thanks for help people.

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