Hello and thanks in advance for any help anyone can offer me

The fast & dirty question is... Why does 'find' return the bash shell scripts when they don't met my criteria?

The longer question is I'm trying to learn the 'find' command and thought I was understanding it... Apparently I was wrong. I was doing compound searches and I started getting weird results with the -size test. I was trying to do a search on a 1G file owned by the user database. I was expecting to get a single file back, but for some reason the 'find' returns not only the 1G file but the scripting files owned by the database user. I've been messing with this for a while trying to understand it. I can filter it out by using a '-not -name ".*" but that's not the point. I want to understand why it's including the start up scripts & what I'm doing wrong. Here's the command and the results... If someone could tell me what I'm doing wrong I would greatly appreciate it!!!

find /home -type f -user database -size 1G -ls
13774125 4 -rw-r--r-- 1 database database 18 Nov 20 2015 /home/database/.bash_logout
13774135 4 -rw-r--r-- 1 database database 193 Nov 20 2015 /home/database/.bash_profile
13774136 4 -rw-r--r-- 1 database database 231 Nov 20 2015 /home/database/.bashrc
13774141 1048576 -rw-r--r-- 1 database root 1073741824 Feb 16 11:10 /home/database/large1.log

Whatever units you specify for size, find will round sizes up to that unit, so "-size 1G" will find all files larger than 0G and no larger than 1G. Think of is as, "If space were allocated in blocks of this size, how many blocks would this file require."

From the man page, numeric arguments can be specified as :
+n for > n
-n for < n
n for exactly n
and for size n says "using n units of space", so you can use -size +1G to match files that use > 1G of space.