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Bash input validation

Posted 01-11-2006 at 09:28 PM by unSpawn

Takes argument and stops when character outside restricted set is found.
Don't know how much slower, didn't run any timing tests with or without yet.

Code:
val_str() {
        declare -r str_allow="1234567890-_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ "
        declare -r str_len="128"; str=( "$1" ); if [ -z "${str}" -o "${#str}" -gt "${str_len}" ]; then return 1; fi
        charLim=$[${#str}-1]; for charPos in $(seq 0 "$charLim"); do char="${str[0]:${charPos}:1}"
        expr index "${char/[\(\)]/!}" "${str_allow} " >/dev/null; case "$?" in 0) ;;*) return 1;; esac; done
 }
Should look for optimisation.
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Comments

  1. Old Comment
    Thank you, I've been searching for something like that!
    I took a closer look and I want to make a suggestion considering expr's return value, cause I don't think it's nice sending it to /dev/null ...

    Code:
    # variables are labeled a bit different here ...
    input=( "$1" )
    charlimit=$[${#input}-1]
    
    for charposition in $(seq 0 "$charlimit"); do
        char="${input[0]:${charposition}:1}"
            # the second for loop takes expr's output, ret_value;
            # if it's 0, the loop returns 1 and we're out
            for ret_value in $(expr index "$char" "${str_allow}"); do
                if [ ${ret_value} == 0 ]; then
                    return 1
                fi
            done
    done
    
    # if the first loop returns 0, return 0;
    # otherwise nothing would be returned
    if [ "${?}" == 0 ]; then
        return 0
    fi
    dP

    Posted 12-31-1969 at 07:00 PM by unSpawn unSpawn is offline
 

  



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